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Simplifying 3[(2r + 3) + -1(r + 1) + -1(r + 2)] = 0 Reorder the terms: 3[(3 + 2r) + -1(r + 1) + -1(r + 2)] = 0 Remove parenthesis around (3 + 2r) 3[3 + 2r + -1(r + 1) + -1(r + 2)] = 0 Reorder the terms: 3[3 + 2r + -1(1 + r) + -1(r + 2)] = 0 3[3 + 2r + (1 * -1 + r * -1) + -1(r + 2)] = 0 3[3 + 2r + (-1 + -1r) + -1(r + 2)] = 0 Reorder the terms: 3[3 + 2r + -1 + -1r + -1(2 + r)] = 0 3[3 + 2r + -1 + -1r + (2 * -1 + r * -1)] = 0 3[3 + 2r + -1 + -1r + (-2 + -1r)] = 0 Reorder the terms: 3[3 + -1 + -2 + 2r + -1r + -1r] = 0 Combine like terms: 3 + -1 = 2 3[2 + -2 + 2r + -1r + -1r] = 0 Combine like terms: 2 + -2 = 0 3[0 + 2r + -1r + -1r] = 0 3[2r + -1r + -1r] = 0 Combine like terms: 2r + -1r = 1r 3[1r + -1r] = 0 Combine like terms: 1r + -1r = 0 3[0] = 0 Multiply 3 * 0 0 = 0 Anything times zero is zero. 0 = 0 Solving 0 = 0 Couldn't find a variable to solve for. This equation is an identity, all real numbers are solutions.
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